a restaurant has a 50 gallon fish tank, the water in the tank evaporates at a rate of -2.5 a week, but the owner adds 3 gallons of water to the tank every 10 days , after the owner added 3 gallons today there were 44 gallons of water in the tank , how much water will be in the tank when the owner adds 3 gallons 70 days from today

The water in the tank 70 days from today will be 42 gallons.Step-by-step explanation:Current water in the tank is 44 gallonsAs per my understanding, water evaporates at -2.5 gallons a weekOwner adds 3 gallons of water every 10 daysTo find water in the tank after 70 days,1. Find the number of weeks in 70 daysa) 1 month = 30 daysx months = 70 daysCross multiply30x = 70x = [tex]\frac{70}{30}[/tex]x = 2.3 monthsb) 1 month = 4 weeks2.3 months = y weeksy = 2.3 x 4y = 9.2 weeksc) Each week, 2.5 gallon evaporates1 week = 2.5 gallon9.2 weeks = z gallonsz = 9.2 x 2.5z = 23 gallons2. After every 10 days, 3 gallons are added.In 70 days, 3 gallons are added 7 times so, 3 x 7 = 21 gallons3. Water in the tank 70 days from today = Water in tank + water added - water evaporatedWater in the tank 70 days from today = 44 + 21 - 23 = 42 gallonsTherefore, the water in the tank 70 days from today will be 42 gallons.Keywords: Equations, gallonsLearn more about equations at